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$(17)^{3.5} \times (17)^{?}=17^{8}$

Answer:

Explanation:

Let $(17)^{3.5} \times (17)^{x}=17^{8}$.

Then, $(17)^{3.5}+x = (17)^{8}$.

$\therefore$ $3.5+x=8$

$\Leftrightarrow x = (8-3.5)$

$\Leftrightarrow x= 4.5$.