Discussion Forum

If $\sqrt{2}$ = 1.414 ,the square root of $\frac{\sqrt{2}-1}{\sqrt{2}+1}$ is nearest to :

Answer:

Explanation:

$\frac{\sqrt{2}-1}{\sqrt{2}+1}=\frac{\sqrt{2}-1}{\sqrt{2}+1}\times\frac{\sqrt{2}-1}{\sqrt{2}-1}= (\sqrt{2}-1)^{2}$
$\sqrt{\frac{\sqrt{2}-1}{\sqrt{2}+1}}=\sqrt{2}-1=1.414-1= 0.414$