1) If $\sqrt{3} = 1.732$, find the value of $\sqrt{196} -\frac{1}{2}\sqrt{48} - \sqrt{75}$ correct to 3 places of decimal. A) 3.254 B) 2.531 C) 1.523 D) 1.732 Answer: Option DExplanation:$\sqrt{192} - \frac{1}{2}\sqrt{48} -\sqrt{75} $$ =\sqrt{64\times 3} -\frac{1}{2}\sqrt{16\times 3}-\sqrt{25\times 3}$= $8\sqrt{3}- \frac{1}{2} \times 4\sqrt{3} -5\sqrt{3} $= $3\sqrt{3}- 2\sqrt{3} $$=\sqrt{3} = 1.732.$
