Answer:
Option B
Explanation:
Given exp.
$=\left(\frac{1}{1^{2}} - \frac{1}{2^{2}}\right) + \left(\frac{1}{2^{2}} - \frac{1}{3^{2}}\right) + \left(\frac{1}{3^{2}} - \frac{1}{4^{2}}\right)+\left(\frac{1}{4^{2}} - \frac{1}{5^{2}}\right)+.....+\left(\frac{1}{9^{2}} - \frac{1}{10^{2}}\right)$
$=\left(\frac{1}{1^{2}} - \frac{1}{10^{2}}\right) =\left(1-\frac{1}{100} \right)$
$=\frac{99}{100}$