Discussion Forum



1)

The value of $\left(1+ \frac{1}{2}\right)\left(1+ \frac{1}{3}\right)\left(1+ \frac{1}{4}\right)---\left(1+ \frac{1}{120}\right)$ is?


A) 30

B) 40.5

C) 60.5

D) 121

Answer:

Option C

Explanation:

Given exp. = $\frac{3}{2} \times \frac{4}{3}\times \frac{5}{4} \times----\times \frac{121}{120}=\frac{121}{120}=60.5$