Discussion Forum

$\frac{3}{4}+2\frac{1}{4}$ of $\frac{2}{3}-\frac{\frac{1}{2}-\frac{1}{3}}{\frac{1}{2}+\frac{1}{3}}\times3\frac{1}{3}+\frac{5}{6}=?$

Answer:

Explanation:

Given = $\frac{3}{4}+2\frac{1}{4}$ of $\frac{2}{3}-\frac{\left(\frac{3-2}{6}\right)}{\left(\frac{3+2}{6}\right)}\times\frac{10}{3}+\frac{5}{6}$
$=\frac{3}{4}+\frac{3}{2}-\frac{1}{6}\times \frac{6}{5}\times\frac{10}{3}+\frac{5}{6}$
$=\frac{3}{4}\times \frac{2}{3}-\frac{2}{3}+\frac{5}{6}$
$=\left(\frac{1}{2}-\frac{2}{3}+\frac{5}{6}\right)$
$\left(\frac{3-4+5}{6}\right)=\frac{4}{6}=\frac{2}{3}$