Discussion Forum

$\frac{5}{6}+\frac{6}{7}\times?-\frac{8}{9}+1\frac{3}{5}+\frac{3}{4}\times3\frac{1}{3}=2\frac{7}{9}$

Answer:

Explanation:

$\frac{5}{6}+\frac{6}{7} \times x-\frac{8}{9}+\frac{8}{5}+\frac{3}{4}\times\frac{10}{3}=\frac{25}{9}$
Then
$\frac{5}{6}\times\frac{7}{6}\times x-\frac{8}{9}\times\frac{5}{8}+\frac{3}{4}\times\frac{10}{3}=\frac{25}{9}$
$\Leftrightarrow\frac{35}{36}x-\frac{5}{9}+\frac{5}{2}$
$\Leftrightarrow\frac{35}{36}x=\frac{25}{9}+\frac{5}{9}-\frac{5}{2}$
$\Leftrightarrow\frac{35}{36}x=\frac{5}{6}$
$\Leftrightarrow x=\left(\frac{5}{6}\times \frac{36}{45}\right)$
$=\frac{6}{7}$