Discussion Forum

$\frac{4335}{4(?)24}+1\frac{7}{8}=\frac{289}{528}$

Answer:

Explanation:

Let $\frac{4335}{x}+\frac{15}{8}=\frac{289}{528}$
Then, $\frac{4335}{x}=\frac{289}{528}\times\frac{15}{8}$
$\Leftrightarrow\frac{4335}{x}=\frac{289\times5}{176\times8}$
$\Leftrightarrow\left(\frac{4335\times176\times8}{289\times5}\right)=4224$
$\therefore$ Missing digit = 2