1)

Which of the following will come in place of both the question marks in the following equation ?

$\frac{128+16 \times ?-7\times 2}{7^{2}-8\times 6+?^{2}}=1$


A) 3

B) 14

C) 16

D) 17

E) 18

Answer:

Option A

Explanation:

Let, $\frac{128\div 16\times x-7\times2}{7^{2}-8\times 6+x^{2}}=1$
=> $8x-7\times 2 = 49-48+x^{2}$
=> $8x-14=1+x^{2}$
=> $x^{2}-8? +15 = 0$
=> (x-3)(x-5)=0
=> x = 3 or x = 5

As we dont have 5 in option x=3