Answer:
Option D
Explanation:
After $10$ years, $SI$ $= \frac{(1000\times 5\times 10)}{100}$ = Rs.500
Principal for $11^{th}$ Year $=1000+500$ = 1500
$SI$ $=2000-1500$ = Rs.500
$T$ $=\frac{(100\times SI)}{P\times R}$
$=\frac{ 500\times 100}{1500\times 5}$
$=6\frac{2}{3}$ Yrs.
Total time $=10+6\frac{2}{3}$ $=16\frac{2}{3}$ Yrs