Discussion Forum



1)

If $A:B=1:3$; $B:C=5:7$; $C:D=9:7$, then $A:B:C:D$ is equal to


A) 15 : 49 : 45 : 63

B) 49 : 15 : 45 : 63

C) 15 : 45 : 63 : 49

D) 45 : 15 : 63 : 49

E) 15: 25 : 63 : 49

Answer:

Option C

Explanation:

$A:B:C:D$ $=1\times 5\times 9:3\times 5\times 9:3\times 7\times 9:3\times 7\times 7$

Taking $3$ as a common factor we get $15:45:63:49$.