Ratio and Proportion | Arithmetic aptitude | Discussion Page

If $A:B=1:3$ ; $B:C=5:7$ ; $C:D=9:7$ , then $A:B:C:D$ is equal to

A) 15 : 49 : 45 : 63

B) 49 : 15 : 45 : 63

C) 15 : 45 : 63 : 49

D) 45 : 15 : 63 : 49

E) 15: 25 : 63 : 49

Option C

$A:B:C:D$ $=1\times 5\times 9:3\times 5\times 9:3\times 7\times 9:3\times 7\times 7$

Taking $3$ as a common factor we get $15:45:63:49$ .

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