Answer:
Option D
Explanation:
Let the required gain percent be $x$%.
Then, $(110$% of $3000)$ $+[(100+x)$% of $3000]$
$=125$% of $6000$
$\Rightarrow$ $\left(\frac{110}{100} \times 3000\right)$ + $\left[\frac{(100+x)}{100} \times 3000\right]$
$=\frac{125}{100} \times 6000$
$\Rightarrow 30(100+x)$
$=4200$ $\Rightarrow (100+x)$ $=140$
$\Rightarrow x = 40$%.