Answer:
Option B
Explanation:
Let the speed of the train be $x$ m/sec.
Time taken to cross a platform = (Length of train + Length of platform) / Speed of the train
Time taken by the train to cross a stationary train = (Sum of the lengths of the train) / Speed of moving train
Time taken to cross a signal pole = Length of train / Speed of train
I gives, $21=\frac{(l+300)}{x}$; II gives, $\frac{39}{2}$ $=\frac{2l}{x}$; III gives, $\frac{39}{4}$ $=\frac{l}{x}$
Thus, (I and II) or (I and III) give $x$.
$\therefore$ Correct answer is (B).