Answer:
Option E
Explanation:
Time taken to cross the train, running in opposite directions $=\frac{\left(l_{1}+l_2\right)}{(u+v)}$ sec.
$\Rightarrow 10$ $=\frac{(210+300)}{(u+v)}$ $\Rightarrow u+v$ $=51$.
Time taken to cross the train, running in same direction $=\frac{\left(l_{1}+l_{2}\right)}{(u-v)}$ sec.
$\Rightarrow 30$ $=\frac{(210+300)}{\left(u-60\times\frac{5}{18}\right)}$ $\Rightarrow u$ $=\left(17+\frac{50}{3}\right)$ m/sec.
Thus, $u$ and $v$ can be obtained.
$\therefore$ Correct answer is (E).