Answer:
Option C
Explanation:
Let the length of the train be $a$ metres.
Time taken to cross a signal post = Length of the train $\div$ Speed of the train $\Rightarrow x=\frac{l}{Speed}$. ----(1)
Time taken to cross the platform $=\frac{(l+100)}{Speed}$ $\Rightarrow y=\frac{l+100}{Speed}$ ----(2)
Thus, from (1) and (2), we can find $l$.
Also II gives, speed $=\left(80\times\frac{5}{18}\right)$ m/s $=\frac{200}{9}$ m/s.
Thus, the data in I or II are sufficient to answer the question.
$\therefore$ The correct answer is (C).