Discussion Forum

A train starts from station X at the rate of 80 km/hr and reaches station Y in 48 min. If the speed is reduced by 8 km/hr. How much more time will the train take to return from station Y to station X ?

Answer:

Explanation:

Distance $xy$ $=\frac{80\times 48 }{60}=64$

New Speed $=80-8=72$ km/hr

Time taken $=\frac{64 }{72}\times 60$ $=53\frac{1 }{3}$ min

Extra time taken $=53\frac{1 }{3}-48$

$=5\frac{1 }{3}$ = 5 min 20 sec