Answer:
Option A
Explanation:
Suppose, the distance between Meerut and Ghaziabad is $x$ km.
Time taken by $X$ to cover $x$ km $=1$ hour.
Time taken by $Y$ to cover $x$ km $=\frac{3}{2}$ hours.
$\therefore$ Speed of $X$ $=x$ kmph, Speed of $Y$ $=\left(\frac{2x}{3}\right)$ kmph.
Let them meet $y$ hours after $4$ p.m. Then,
$xy+\frac{2xy}{3}=x$ $\Leftrightarrow y\left(1+\frac{2}{3}\right)=1$
$\Leftrightarrow y=\frac{3}{5}$ hours $=\left(\frac{3}{5}\times 60\right)$ min$=36$ min.
So, the two trains meet at 4.36 p.m.