Answer:
Option D
Explanation:
Speed of first train $=\left(\frac{150}{15}\right)$ m/sec = 10 m/sec.
Let the speed of the second train be $x$ m/sec.
Relative speed $=(10+x)$ m/sec.
$\therefore\frac{300}{10+x}=8$ $\Leftrightarrow 300=80+8x$
$\Leftrightarrow x=\frac{220}{8}$ $=\frac{55}{2}$ m/sec.
So, speed of second train $=\left(\frac{55}{2}\times\frac{18}{5}\right)$ kmph = 99 kmph.