Answer:
Option A
Explanation:
Let the speed of train $Y$ be $x$ km/hr.
Speed of $X$ relative to $Y$ $=(120-x)$ km/hr.
$=\left[(120-x)\times\frac{5}{18}\right]$ m/sec $=\left(\frac{600-5x}{18}\right)$ m/sec.
$\therefore$ $\frac{300}{\left(\frac{600-5x}{18}\right)}=120$ $\Leftrightarrow 5400=120(600-5x)$
$\Leftrightarrow x=111$.