Answer:
Option A
Explanation:
Relative speed $=(120+80)$ km/hr $=\left(200\times\frac{5}{18}\right)$ m/sec $=\left(\frac{500}{9}\right)$ m/sec.
Let the length of the other train be $x$ metres.
Then, $\frac{x+270}{9}$ $=\frac{500}{9}$
$\Leftrightarrow x+270$ $=500$
$\Leftrightarrow x=230$.