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A train crosses a platform 100 m long in 60 seconds at a speed of 45 km/hr. The time taken by the train to cross an electric pole is :

Answer:

Explanation:

Speed $=\left(45\times\frac{5}{18}\right)$ m/sec $=\left(\frac{25}{2}\right)$ m/sec.

Let the length of the train be $x$ metres.

Then, $\frac{x+100}{\left(\frac{25}{2}\right)}$ or $x=650$ m

$\therefore$ Time taken by the train to cross an electric pole $=\left(650\times\frac{2}{25}\right)$ sec = 52 sec.