1) The product of two numbers is 120 and the sum of their squares is 289. The sum of the numbers is : A) 20 B) 23 C) 169 D) 175 E) None of these Answer: Option BExplanation:Let the numbers be $x$ and $y$. Then, $xy=120$ and $x^{2}+y^{2}=289$.$\therefore$ $(x+y)^{2}=x^{2}+y^{2}+2xy=289+240=529$.$\therefore x+y = \sqrt{529}=23$
