Discussion Forum

The product of two numbers is 120 and the sum of their squares is 289. The sum of the numbers is :

Answer:

Explanation:

Let the numbers be $x$ and $y$. Then, $xy=120$ and $x^{2}+y^{2}=289$.
$\therefore$ $(x+y)^{2}=x^{2}+y^{2}+2xy=289+240=529$.
$\therefore x+y = \sqrt{529}=23$