Discussion Forum

Karan was 4 times as old as his son 8 years ago. After 8 years, Karan will be twice as old as his son. What are their present ages?.

Answer:

Explanation:

Let the son's age 8 years ago be $x$ years. Then, Karan's age 8 years ago $=4x$ years.
Son'e age after 8 years $=(4x+8)+8$ $=(4x+16)$ years.
$\therefore $ $2(x+16)$ $=4x+16$
$\Leftrightarrow 2x = 16$ $\Leftrightarrow x=8$.
Hence, son's present age $=(x+8)$ $= 16$ years.
Karan's present age $=(4x+8)$ $=40$ years.