Discussion Forum

A boy after giving away 80% of his pocket money to one companion and 6% of the remainder to another has 47 paisa left with him. How much pocket money did the boy have in the beginning?

Answer:

Explanation:

Let the boy had = Rs.x

Money given to first companion $= 80$% of $x = \frac{4x}{5}$

Remaining money $= \left(x-\frac{4x}{5}\right)$ $= \frac{x}{5}$

Money given to $2^{nd}$ companion $= \left(\frac{x}{5}\right)\times \left(\frac{6}{100}\right)$ $=\frac{3x}{250}$

Remaining money $= \left(\frac{x}{5}\right)-\left(\frac{3x}{250}\right)$ $= \frac{47x}{250}$

Then $\frac{47x}{250}$ $=\frac{47}{100}$

$\therefore$ $x = \left(\frac{47}{100}\right)\times \left(\frac{250}{47}\right)$

$=$ Rs.$2.50$