1)

If  two numbers are respectively 30% and 40 % more than a third number ,what the percent is the first o the second ?


A) 85%

B) $92\frac{6}{7}$ %

C) $92\frac{7}{6}$

D) $79\frac{6}{7}$

E) $92\frac{7}{6}$

Answer:

Option B

Explanation:

Let $3^{rd}$ number = 100

Then $1^{st}$ and $2^{nd}$ numbers are 130 and 140

First as a percentage of second $= \left(\frac{130}{140}\right)\times 100$

= $92\frac{6}{7}$%