1)

If log m + log n = log(m+n) then m is given by


A) n+12

B) n+1n

C) nn1

D) None of these

Answer:

Option C

Explanation:

log m +log n = log(m+n)

(hence,log a + log b = log ab)

log (mn) = log (m+n)

mn=m+n

mn-n=n

m(n-1)=n

m=nn1