1) If log m + log n = log(m+n) then m is given by A) $\frac{n+1}{2}$ B) $\frac{n+1}{n}$ C) $\frac{n}{n-1}$ D) None of these Answer: Option CExplanation:log m +log n = log(m+n) (hence,log a + log b = log ab) log (mn) = log (m+n) mn=m+n mn-n=n m(n-1)=n m=$\frac{n}{n-1}$
