1)

1logxyxyz+1logyzxyz+1logzxxyz is


A) 1

B) 2

C) log 2

D) 12

Answer:

Option B

Explanation:

1logxyxyz+1logyzxyz+1logzxxyz 

= logxyzxy+logxyzyz+logxyzzx

=logxyzxy×yz×zx

=logxyz(xyz)2

=2logxyzxyz

=2\times 1

=2