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$log\left(\frac{a^{2}}{bc}\right)$ $+log\left(\frac{b^{2}}{ac}\right)$ $+log\left(\frac{c^{2}}{ab}\right)$ is equal to

Answer:

Explanation:

Given expression = $log \left(\frac{a^{2}}{bc}\times\frac{b^{2}}{ac}\times\frac{c^{2}}{ab}\right)$ = log 1 = 0.