Discussion Forum

Find the value of $log_{\sqrt{2}}32$

Answer:

Explanation:

Let $log_{\sqrt{2}}32$ $=n$

Then, $(\sqrt{2})^{n}$ $=32$

$\Leftrightarrow (2)^{n/2}$ $=2^{5}$

$\Leftrightarrow \frac{n}{2}$ $=5$

$\Leftrightarrow n=10$

$\therefore log_{\sqrt{2}}32$ $=10$