Discussion Forum

Let the least number of six digits, which when divided by 4, 6, 10 and 15 leaves in each case the same remainder of 2, be N. The sum of the digits in N is :

Answer:

Explanation:

LCM of 4, 6, 10, 15 = 60
Least number of 6 digits = 100000
The leats number of 6 digits which is exactly divisible by 60 = 100000 + (60 – 40) = 100020
Required Number = 100020 + 2 = 100022
Hence, the sum of digits = 1 + 0 + 0 + 0 + 2 + 2 = 5