Discussion Forum

The H.C.F. and L.C.M of two numbers are 11 and 385 respectively. If one number lies between 75 and 125, then that number is :

Answer:

Explanation:

Product of numbers = 11 x 385 = 4235
Let the numbers be 11c and 11d . Then , 11c x 11d = 4235 => cd = 35
Now, co-primes with product 35 are (1,35) and (5,7)
So, the numbers are ( 11 x 1, 11 x 35) and (11 x 5, 11 x 7)
Since one number lies 75 and 125, the suitable pair is (55,77)
Hence , required number = 77