Answer:
Option D
Explanation:
I gives, Amount after $2$ years = Rs. $11025$, when compounded.
II gives, Amount after $2$ years at $S.I.$ = Rs. $11000$.
III gives, Principal = Rs. $10000$.
From II and III, we have :
Principal = Rs. $10000$, $S.I.$ = Rs. $(11000-10000)$ = Rs. $1000$ and Time = $2$ years.
Hence, Rate can be calculated.
$\therefore$ I is redundant.
From I and III, we get $11025$ $=10000\times \left(1+\frac{R}{100}\right)^{2}$. This gives $R$.
$\therefore$ II is redundant.
From I and II, we have
$P\left(1+\frac{R}{100}\right)^{2}$ $=11025$ ---(i)
and $P\left[1+\frac{R\times 2}{100}\right]$ $=11000$ ---(ii)
On dividing (i) by (ii), we get $\frac{\left(1+\frac{R}{100}\right)^{2}}{(50+R)}$ $=\frac{11025}{550000}$.
This gives $R$.
Thus, III is redundant.
Hence I or II or II is redundant.