Answer:
Option D
Explanation:
I gives, Amount after 2 years = Rs. 11025, when compounded.
II gives, Amount after 2 years at S.I. = Rs. 11000.
III gives, Principal = Rs. 10000.
From II and III, we have :
Principal = Rs. 10000, S.I. = Rs. (11000−10000) = Rs. 1000 and Time = 2 years.
Hence, Rate can be calculated.
∴ I is redundant.
From I and III, we get 11025 =10000×(1+R100)2. This gives R.
∴ II is redundant.
From I and II, we have
P(1+R100)2 =11025 ---(i)
and P[1+R×2100] =11000 ---(ii)
On dividing (i) by (ii), we get (1+R100)2(50+R) =11025550000.
This gives R.
Thus, III is redundant.
Hence I or II or II is redundant.