Answer:
Option D
Explanation:
Let rate upstream $=x$ km/hr and rate downstream $=y$ km/hr.
Then, $\frac{40}{x}$ $+\frac{55}{y}$ $= 13$ ...(i)
and $\frac{30}{x}$ $+\frac{44}{y}$ $=10$ ...(ii)
Multiplying (ii) by 4 and (i) by 3 and subtracting, we get : $\frac{11}{y}$ $=1$ or $y$ $=11$.
Substituting $y=11$ in (i), we get : $x=5$.
$\therefore$ Rate in still water $=\frac{1}{2} (11+5)$ kmph = 8 kmph.
Rate of current $=\frac{1}{2} (11-5)$ kmph = 3 kmph.