1)

The average price of 10 books is Rs. 12 while the average price of 8 of these books is Rs. 11.75. Of the remaining two books, if the price of one book is 60% more than the price of the other, what is the price of each of these two books ?


A) Rs. 5, Rs. 7.50

B) Rs. 8, Rs. 12

C) Rs. 10, Rs. 16

D) Rs. 12, Rs. 14

Answer:

Option C

Explanation:

Total price of the two books = [(12x10)-(11.75x8)]
= 120-94 = 26
Let the price of one book be x
then the price of the other book = (x+60% of x) = $x+\frac{3}{5}x=\frac{8x}{5}$
So $x+\frac{8x}{5}=26$ => 13x=130=> x=10
The price of the two books are Rs.10 and Rs.16