Discussion Forum



1)

16 children are to be divided into two groups A and B of 10 and 6 children. The average percent marks obtained by the children pf group A is 75 and the average percent marks of all the 16 children is 76. What is the average percent marks of children of group B ?


A) $77\frac{1}{3}$

B) $77\frac{2}{3}$

C) $78\frac{1}{3}$

D) $78\frac{2}{3}$

Answer:

Option B

Explanation:

$\frac{(76\times16)-(75\times10)}{6}=\frac{1216-750}{6}=\frac{466}{6}=\frac{233}{3}=77\frac{2}{3}$