1) The average of the two-digit numbers, which remain the same when the digits interchange their positions, is : A) 33 B) 44 C) 55 D) 66 Answer: Option CExplanation:Average = $\frac{11+22+33+44+55+66+77+88+99}{9}$$=\frac{(11+99)+(22+88)+(33+77)+(44+66)+55}{9}$$=\frac{4\times110+55}{9}=\frac{495}{9}=55$