Discussion Forum

A and B are two alloys of gold and copper prepared by mixing metals in proportion of 5 : 3 and 5 : 11 respectively.If equal quantities of these alloys are melted to form a third alloy C, what would be the proportion of gold and copper in the alloy C, thus formed?

Answer:

Explanation:

Let gold and copper be 5x and 3x in first alloy.In second alloy, let gold and copper be 5y and 11 y.

Equal quantitis are mixed to form alloy C.

5x+3x=5y+11y

x=2y

Amount of gold in alloy C =5x+5y=10y+5y=15y

Amount of copper in alloy C=3x+11y=6y+11+=17y

Required ratio=15y : 17y=15 : 17