Discussion Forum

1)

In the following monobromination reaction, the number of possible chiral product (s)  is (are ).....

Answer:

Option C

Explanation:

Given compound undergoes free-radical  bromination under given conditions, replacing H by Br

$C^{*}$ is chiral carbon.

(III)   has two chiral centres and can have two structures.

(IV)  has also two chiral centres and can have two structures,

  

 

 It has the plane of symmetry thus, achiral. Thus, chiral compounds are five. I, III-A, III-B, IV-B, V.