Discussion Forum

A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed :

Answer:

Explanation:

Let the total number of shots be x. Then,
Shots fired by A = $\frac{5}{8}x$
Shots fired by B = $\frac{3}{8}x$
Killing shots by A = $\frac{1}{3}=\frac{5}{24}x$
Shots missed by B = $\frac{1}{2}=\frac{3}{16}x$
$\therefore \frac{3x}{16} = 27$
or x = $\left(\frac{27 \times 16}{3}\right)= 144$
Birds Killed by A = $\frac{5x}{24}=\left(\frac{5}{24} \times 144 \right)=30$