1)

A train X starts from Meerut at 4 p.m. and reaches Ghaziabad at 5 p.m. while another train Y starts from Ghaziabad at 4 p.m. and reaches Meerut at 5.30 p.m. The two trains, will cross each other at :


A) 4.36 p.m.

B) 4.42 p.m.

C) 4.48 p.m.

D) 4.50 p.m.

E) 5.50 p.m.

Answer:

Option A

Explanation:

Suppose, the distance between Meerut and Ghaziabad is $x$ km.

Time taken by $X$ to cover $x$ km $=1$ hour.

Time taken by $Y$ to cover $x$ km $=\frac{3}{2}$ hours.

$\therefore$ Speed of $X$ $=x$ kmph, Speed of $Y$ $=\left(\frac{2x}{3}\right)$ kmph.

Let them meet $y$ hours after $4$ p.m. Then,

$xy+\frac{2xy}{3}=x$ $\Leftrightarrow y\left(1+\frac{2}{3}\right)=1$

$\Leftrightarrow y=\frac{3}{5}$ hours $=\left(\frac{3}{5}\times 60\right)$ min$=36$ min.

So, the two trains meet at 4.36 p.m.