Answer:
Option A
Explanation:
$C.I$ $=p\left[\left(1+ \frac{R}{100}\right)^{T}-1\right]$
$\Rightarrow p\left[\left(1+ \frac{5}{100}\right)^{2}-1\right]$
$\Rightarrow 328$ $=p\left(\frac{441}{400}-1\right)$
$\Rightarrow 328$ $=p\left(\frac{41}{100}\right)$
$\Rightarrow p$ $=\frac{328 \times 400}{41}$ $=3200$
$SI$ $=\frac{PRT}{100}$ $=\frac{3200\times 5\times 2}{100}$ = Rs. 320.